Discount calculation strange with ‘3 for 2’
If I have a discount promotion that triggers ‘3 for 2’ (i.e. the cheapest product for free), the calculation is different than you would expect.
As long as there is a sufficient quantity of the cheapest product in the shopping cart, the discount will be applied to it. For example, if ‘A’ is in the shopping cart 6 times, ‘B’ must be present twice so that the cheapest product can be clearly calculated. If ‘A’ is 9x, ‘B’ must be in the shopping cart 3x. If the quantity of the cheapest product is lower, the second three products must be calculated on the more expensive product, which means that there must be one more product in the position.
This is not logical: if, for example, I have 2x the cheapest and 7x the expensive one, I expect to get 3 for free - because there are 9 items.
And if there are only 2x the cheapest, then I get 2x the cheapest and 1x the expensive one for free.
Rachel Booth
shared this idea
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Nils Rau
commented
Please fix this as fast as possible - This way to calculate is very uncommon and leads to much effort at our customer's service teams.